create table StudentList(
id int Identity(1,1) not null,
Name nvarchar(20) not null,
Sex bit not null,
Birthday date not null,
Class nvarchar(2) not null,
Grade nvarchar(2) not null,
regdate date not null,
Primary key (id));
create table ScoreInfo(
id int Identity(1,1) not null primary key,
StudentID int not null,
ClassID int not null,
Score int not null,
TestDate date not null,
regdate date not null);
insert into StudentList(Name, Sex, Birthday, Class, Grade, regdate) values('張三', 1, '1988-05-28', 1, 8, '2010-05-05');
insert into StudentList(Name, Sex, Birthday, Class, Grade, regdate) values('李四', 1, '1985-09-13', 4, 4, '2010-05-05');
insert into StudentList(Name, Sex, Birthday, Class, Grade, regdate) values('王麗', 0, '1987-11-05', 1, 7, '2010-05-05');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(1, 1, 98, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(1, 2, 92, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(1, 3, 86, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(2, 1, 95, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(2, 2, 94, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(2, 3, 91, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(3, 1, 90, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(3, 2, 88, '2010-04-15', '2010-05-01');
insert into ScoreInfo(StudentID, ClassID, Score, TestDate, regdate) values(3, 3, 90, '2010-04-15', '2010-05-01');
Cross Apply把語句兩邊的兩個Select查詢結果進行交叉配對，將所有結果展示出來。Cross Apply查詢確保在查詢兩個子集數據的交集時，只有有效信息的集合才被列出來。
